0.3x-0.03x^2=0

Solution for 0.3x-0.03x^2=0 equation:

0.3x-0.03x^2=0

a = -0.03; b = 0.3; c = 0;
Δ = b2-4ac
Δ = 0.32-4·(-0.03)·0
Δ = 0.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.3)-\sqrt{0.09}}{2*-0.03}=\frac{-0.3-\sqrt{0.09}}{-0.06}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.3)+\sqrt{0.09}}{2*-0.03}=\frac{-0.3+\sqrt{0.09}}{-0.06}
$